What you'll learn
- Match IR, UV-Vis and 1H NMR spectra to structures
- Identify functional groups from characteristic IR wavenumbers
- Apply the Beer-Lambert law for UV-Vis quantitation
- Read 1H NMR chemical shift, integration and splitting
Match IR, UV-Vis and 1H NMR spectra to structures and choose the right technique for each question.
Why it matters
Spectroscopy uses the interaction of light (electromagnetic radiation) with matter to identify compounds and measure how much is present. Three techniques do most of the everyday work: infrared (IR) for functional groups and identity tests, UV-Visible for quantitation, and nuclear magnetic resonance (NMR) for full structure. A pharmacopoeia identity test, for example, often requires the sample's IR spectrum to match a reference standard's. Analysts need to read all three at a basic level and know which one answers which question.
IR: which bonds are present?
IR light makes bonds vibrate. Each type of bond absorbs at a characteristic wavenumberThe IR position unit (cm^-1) at which a type of bond absorbs. (cm^-1). Key regions:
| Bond | Wavenumber (cm^-1) | Look |
|---|---|---|
| O-H (alcohol) | 3200 to 3550 | Broad, strong |
| O-H (carboxylic acid) | 2500 to 3300 | Very broad, overlapping C-H |
| N-H | 3300 to 3500 | Sharper; primary amines show two peaks |
| C-H (sp3) | 2850 to 3000 | Just below 3000 |
| C-H (sp2, alkene or aromatic) | 3000 to 3100 | Just above 3000 |
| C≡N | about 2250 | Sharp, medium |
| C=O | 1650 to 1750 | Strong, sharp (ketones about 1715, esters about 1735) |
| C=C | 1600 to 1680 | Medium |
Below about 1500 cm^-1 is the fingerprint regionThe IR region below about 1500 cm^-1, too complex to assign but unique to each compound, so used for identity matching.: too complex to assign peak by peak, but unique to each compound, which is why it is used for identity matching. Most labs now use ATR-FTIR, which needs only a drop or a few milligrams pressed on a crystal.
UV-Vis: how much is present?
UV-Vis light promotes electrons to higher energy levels. Molecules with conjugatedAlternating double bonds; more conjugation shifts UV-Vis absorption to longer wavelengths. double bonds or aromatic rings absorb in the UV or visible range; more conjugation shifts absorption to longer wavelengths (that is why highly conjugated dyes are colored). UV-Vis spectra are broad and not very specific, but quantitation is excellent through the Beer-Lambert lawA = epsilon x b x c: absorbance is proportional to concentration and path length.:
A = epsilon x b x cwith absorbance A, molar absorptivity epsilon (L mol^-1 cm^-1), path length b (cm) and concentration c (mol/L). The law holds best at absorbances of roughly 0.1 to 1. Calibration curves were covered in lab-techniques-instrumentation and lab-data-quality; HPLC UV detectors apply the same law.
NMR: how are the atoms connected?
In a strong magnetic field, nuclei such as 1H and 13C absorb radio waves at frequencies that depend on their chemical surroundings. A 1H NMR spectrum tells you three things:
- Chemical shiftThe position of an NMR signal in ppm, which reflects the chemical environment of the nucleus. (ppm): the environment. Alkyl C-H about 0.9 to 1.5; H next to C=O about 2.0 to 2.5; H on a carbon bearing oxygen about 3.3 to 4.5; alkene H about 4.5 to 6.5; aromatic H about 6.5 to 8; aldehyde H about 9 to 10; carboxylic acid H about 10 to 12.
- Integration: the area of each signal is proportional to the number of H atoms.
- Splitting (n + 1 ruleA 1H NMR signal is split into n + 1 lines by n equivalent neighboring H atoms.): a signal is split into n + 1 lines by n equivalent neighboring H atoms. A CH3 next to a CH2 is a triplet; the CH2 next to a CH3 is a quartet.
Worked example: matching spectra to structures
Two isomers of C2H6O: ethanol (CH3CH2OH) and dimethyl ether (CH3OCH3).
- IR: ethanol shows a broad O-H band near 3300 cm^-1; dimethyl ether has none.
- 1H NMR: dimethyl ether has all six H in one environment, giving one singlet (about 3.2 ppm). Ethanol gives three signals: a triplet (3H, about 1.2 ppm), a quartet (2H, about 3.7 ppm) and an OH signal (1H, position varies).
A second case: a compound shows a strong IR band at 1715 cm^-1, no O-H, and a 1H NMR singlet of 6H near 2.1 ppm. A ketone with two equivalent CH3 groups next to C=O: acetone.
Which technique for which question?
- "Is this the right material?" IR against a reference spectrum.
- "How much is in the solution?" UV-Vis (or HPLC-UV).
- "What is the structure of this unknown or impurity?" NMR, with MS for mass and IR for functional groups.
Common mistakes
- Trying to assign every peak in the IR fingerprint region.
- Reading an absorbance above about 1.5 and trusting Beer-Lambert linearity.
- Forgetting that NMR integration gives relative numbers of H.
- Counting neighbors across an oxygen in the n + 1 rule (coupling through O-H is often not seen because the OH proton exchanges).
Quick recap
- IR: functional groups and identity; C=O near 1700, O-H broad near 3300.
- UV-Vis: quantitation with A = epsilon b c; conjugation shifts absorbance to longer wavelengths.
- 1H NMR: shift (environment), integration (how many H), splitting (n + 1 neighbors).
- Combine IR, NMR and MS to determine a structure.
Try it
Open the Do tab for the quiz: match spectra to structures.
Key terms (6)
- wavenumber
- The IR position unit (cm^-1) at which a type of bond absorbs.
- fingerprint region
- The IR region below about 1500 cm^-1, too complex to assign but unique to each compound, so used for identity matching.
- Beer-Lambert law
- A = epsilon x b x c: absorbance is proportional to concentration and path length.
- Chemical shift
- The position of an NMR signal in ppm, which reflects the chemical environment of the nucleus.
- n + 1 rule
- A 1H NMR signal is split into n + 1 lines by n equivalent neighboring H atoms.
- conjugated
- Alternating double bonds; more conjugation shifts UV-Vis absorption to longer wavelengths.